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The time now is Wed 19 Jun 2013, 18:17 All times are UTC - 4 |
 Forum index » Off-Topic Area » Programming |
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executing .sh scripts inside another .sh script
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tatamata
Joined: 02 May 2010 Posts: 63 |
Hello. There is an script1.sh which executes other .sh scripts in this way: ./dir1/dir2/script2.sh ./dir1/dir3/script3.sh This was for Ubuntu or such linux systems where you don't have to explicitely do: sh scrip.sh.... So, I tried with sh ./dir1/dir2/script2.sh sh ./dir1/dir3/script3.sh but this doesn't work I can go with cd ./dir1/dir2/ script2.sh cd .. cd.. cd ./dir1/dir3/ sh script3.sh but, obviously this is bad way to do it. Is there a better way, in order not to go with cd? |
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Bruce B
 Joined: 18 May 2005 Posts: 10823 Location: The Peoples Republic of California |
the script files will run the interpreter in the SHELL= variable unless otherwise specified. sh is not Puppy's default, bash is the first line of the .sh file should look like this #!/bin/sh the file itself needs to have, or should have the executable bit set, typically I do it like this chmod 755 shell.sh If you put the file in a directory in the PATH= statement, all you need to is say its name to run it echo $PATH shows the directories which are set. It might have this directory /root/bin, if so, that would be a good place to put your toys
Do not ./dir1, the ./ makes it a relative path and it will only run if the script1.sh is ran from the parent directory Put script2 and script3 in the path and all script1 needs to say is:
If you don't have script1 and script2 in the path, then use full path to each, like this
You don't need the .sh extension. Using it will primarily make it easier for you to recognize which type of script it is. I've never actually wrote a script using sh or tested any of my advice, but I wanted to make sure you got some kind of help, and I think my advice is accurate, if not it will make for critique from someone and I can learn more. ~ _________________ New! Puppy Linux Links Page |
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L18L
Joined: 19 Jun 2010 Posts: 1802 Location: Burghaslach, Germany |
I have been trying too. ... and it works 
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executing .sh scripts inside another .sh script
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